No, it's both. That's why the problem has no solution.

It's x^(x^2) not (x^x)^2. And in fact, for x = sqrt(2) we have x^(x^2) = x^2 = 2
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Pablo Emanuel
Remarkl
·Follow
Mar 7, 2024
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No, it's both. That's why the problem has no solution.
Bela "solved" the problem by substituting 2 for all of the exponents. I "solved" it by substituting 2 for all of the exponents of (x^x). Why is she allowed to do what she did but I am not allowed to do what I did?
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Written by Remarkl437 Followers
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